3.39 \(\int \frac{(a g+b g x)^3 (A+B \log (\frac{e (a+b x)}{c+d x}))}{(c i+d i x)^2} \, dx\)

Optimal. Leaf size=341 \[ -\frac{3 b B g^3 (b c-a d)^2 \text{PolyLog}\left (2,\frac{d (a+b x)}{b (c+d x)}\right )}{d^4 i^2}-\frac{g^3 (a+b x)^2 (b c-a d) \left (3 B \log \left (\frac{e (a+b x)}{c+d x}\right )+3 A+B\right )}{2 d^2 i^2 (c+d x)}-\frac{b g^3 (b c-a d)^2 \log \left (\frac{b c-a d}{b (c+d x)}\right ) \left (6 B \log \left (\frac{e (a+b x)}{c+d x}\right )+6 A+5 B\right )}{2 d^4 i^2}-\frac{g^3 (6 A+5 B) (a+b x) (b c-a d)^2}{2 d^3 i^2 (c+d x)}+\frac{g^3 (a+b x)^3 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{2 d i^2 (c+d x)}-\frac{3 B g^3 (a+b x) (b c-a d)^2 \log \left (\frac{e (a+b x)}{c+d x}\right )}{d^3 i^2 (c+d x)}+\frac{3 B g^3 (a+b x) (b c-a d)^2}{d^3 i^2 (c+d x)} \]

[Out]

(3*B*(b*c - a*d)^2*g^3*(a + b*x))/(d^3*i^2*(c + d*x)) - ((6*A + 5*B)*(b*c - a*d)^2*g^3*(a + b*x))/(2*d^3*i^2*(
c + d*x)) - (3*B*(b*c - a*d)^2*g^3*(a + b*x)*Log[(e*(a + b*x))/(c + d*x)])/(d^3*i^2*(c + d*x)) + (g^3*(a + b*x
)^3*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(2*d*i^2*(c + d*x)) - ((b*c - a*d)*g^3*(a + b*x)^2*(3*A + B + 3*B*Lo
g[(e*(a + b*x))/(c + d*x)]))/(2*d^2*i^2*(c + d*x)) - (b*(b*c - a*d)^2*g^3*Log[(b*c - a*d)/(b*(c + d*x))]*(6*A
+ 5*B + 6*B*Log[(e*(a + b*x))/(c + d*x)]))/(2*d^4*i^2) - (3*b*B*(b*c - a*d)^2*g^3*PolyLog[2, (d*(a + b*x))/(b*
(c + d*x))])/(d^4*i^2)

________________________________________________________________________________________

Rubi [A]  time = 0.727061, antiderivative size = 519, normalized size of antiderivative = 1.52, number of steps used = 22, number of rules used = 14, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.35, Rules used = {2528, 2486, 31, 2525, 12, 72, 44, 2524, 2418, 2394, 2393, 2391, 2390, 2301} \[ -\frac{3 b B g^3 (b c-a d)^2 \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )}{d^4 i^2}-\frac{a^2 b B g^3 \log (a+b x)}{2 d^2 i^2}+\frac{b^3 g^3 x^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{2 d^2 i^2}-\frac{A b^2 g^3 x (2 b c-3 a d)}{d^3 i^2}+\frac{g^3 (b c-a d)^3 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{d^4 i^2 (c+d x)}+\frac{3 b g^3 (b c-a d)^2 \log (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{d^4 i^2}-\frac{b^2 B g^3 x (b c-a d)}{2 d^3 i^2}-\frac{b B g^3 (a+b x) (2 b c-3 a d) \log \left (\frac{e (a+b x)}{c+d x}\right )}{d^3 i^2}-\frac{B g^3 (b c-a d)^3}{d^4 i^2 (c+d x)}+\frac{3 b B g^3 (b c-a d)^2 \log ^2(c+d x)}{2 d^4 i^2}-\frac{b B g^3 (b c-a d)^2 \log (a+b x)}{d^4 i^2}-\frac{3 b B g^3 (b c-a d)^2 \log (c+d x) \log \left (-\frac{d (a+b x)}{b c-a d}\right )}{d^4 i^2}+\frac{b B g^3 (b c-a d)^2 \log (c+d x)}{d^4 i^2}+\frac{b B g^3 (2 b c-3 a d) (b c-a d) \log (c+d x)}{d^4 i^2}+\frac{b^3 B c^2 g^3 \log (c+d x)}{2 d^4 i^2} \]

Antiderivative was successfully verified.

[In]

Int[((a*g + b*g*x)^3*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(c*i + d*i*x)^2,x]

[Out]

-((A*b^2*(2*b*c - 3*a*d)*g^3*x)/(d^3*i^2)) - (b^2*B*(b*c - a*d)*g^3*x)/(2*d^3*i^2) - (B*(b*c - a*d)^3*g^3)/(d^
4*i^2*(c + d*x)) - (a^2*b*B*g^3*Log[a + b*x])/(2*d^2*i^2) - (b*B*(b*c - a*d)^2*g^3*Log[a + b*x])/(d^4*i^2) - (
b*B*(2*b*c - 3*a*d)*g^3*(a + b*x)*Log[(e*(a + b*x))/(c + d*x)])/(d^3*i^2) + (b^3*g^3*x^2*(A + B*Log[(e*(a + b*
x))/(c + d*x)]))/(2*d^2*i^2) + ((b*c - a*d)^3*g^3*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(d^4*i^2*(c + d*x)) +
(b^3*B*c^2*g^3*Log[c + d*x])/(2*d^4*i^2) + (b*B*(2*b*c - 3*a*d)*(b*c - a*d)*g^3*Log[c + d*x])/(d^4*i^2) + (b*B
*(b*c - a*d)^2*g^3*Log[c + d*x])/(d^4*i^2) - (3*b*B*(b*c - a*d)^2*g^3*Log[-((d*(a + b*x))/(b*c - a*d))]*Log[c
+ d*x])/(d^4*i^2) + (3*b*(b*c - a*d)^2*g^3*(A + B*Log[(e*(a + b*x))/(c + d*x)])*Log[c + d*x])/(d^4*i^2) + (3*b
*B*(b*c - a*d)^2*g^3*Log[c + d*x]^2)/(2*d^4*i^2) - (3*b*B*(b*c - a*d)^2*g^3*PolyLog[2, (b*(c + d*x))/(b*c - a*
d)])/(d^4*i^2)

Rule 2528

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*(RGx_), x_Symbol] :> With[{u = ExpandIntegrand[(a + b*Log[c*
RFx^p])^n, RGx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, p}, x] && RationalFunctionQ[RFx, x] && RationalF
unctionQ[RGx, x] && IGtQ[n, 0]

Rule 2486

Int[Log[(e_.)*((f_.)*((a_.) + (b_.)*(x_))^(p_.)*((c_.) + (d_.)*(x_))^(q_.))^(r_.)]^(s_.), x_Symbol] :> Simp[((
a + b*x)*Log[e*(f*(a + b*x)^p*(c + d*x)^q)^r]^s)/b, x] + Dist[(q*r*s*(b*c - a*d))/b, Int[Log[e*(f*(a + b*x)^p*
(c + d*x)^q)^r]^(s - 1)/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, p, q, r, s}, x] && NeQ[b*c - a*d, 0] &&
EqQ[p + q, 0] && IGtQ[s, 0]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 2525

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)*((d_.) + (e_.)*(x_))^(m_.), x_Symbol] :> Simp[((d + e*x)^(m
+ 1)*(a + b*Log[c*RFx^p])^n)/(e*(m + 1)), x] - Dist[(b*n*p)/(e*(m + 1)), Int[SimplifyIntegrand[((d + e*x)^(m +
1)*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x], x] /; FreeQ[{a, b, c, d, e, m, p}, x] && RationalFunc
tionQ[RFx, x] && IGtQ[n, 0] && (EqQ[n, 1] || IntegerQ[m]) && NeQ[m, -1]

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 72

Int[((e_.) + (f_.)*(x_))^(p_.)/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Int[ExpandIntegrand[(
e + f*x)^p/((a + b*x)*(c + d*x)), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && IntegerQ[p]

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 2524

Int[((a_.) + Log[(c_.)*(RFx_)^(p_.)]*(b_.))^(n_.)/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[(Log[d + e*x]*(a + b
*Log[c*RFx^p])^n)/e, x] - Dist[(b*n*p)/e, Int[(Log[d + e*x]*(a + b*Log[c*RFx^p])^(n - 1)*D[RFx, x])/RFx, x], x
] /; FreeQ[{a, b, c, d, e, p}, x] && RationalFunctionQ[RFx, x] && IGtQ[n, 0]

Rule 2418

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*(RFx_), x_Symbol] :> With[{u = ExpandIntegrand[
(a + b*Log[c*(d + e*x)^n])^p, RFx, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[{a, b, c, d, e, n}, x] && RationalFunct
ionQ[RFx, x] && IntegerQ[p]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2390

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_))^(q_.), x_Symbol] :> Dist[1/
e, Subst[Int[((f*x)/d)^q*(a + b*Log[c*x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, f, g, n, p, q}, x]
&& EqQ[e*f - d*g, 0]

Rule 2301

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*x^n])^2/(2*b*n), x] /; FreeQ[{a
, b, c, n}, x]

Rubi steps

\begin{align*} \int \frac{(a g+b g x)^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{(39 c+39 d x)^2} \, dx &=\int \left (-\frac{b^2 (2 b c-3 a d) g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^3}+\frac{b^3 g^3 x \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^2}+\frac{(-b c+a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^3 (c+d x)^2}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{507 d^3 (c+d x)}\right ) \, dx\\ &=\frac{\left (b^3 g^3\right ) \int x \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \, dx}{1521 d^2}-\frac{\left (b^2 (2 b c-3 a d) g^3\right ) \int \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \, dx}{1521 d^3}+\frac{\left (b (b c-a d)^2 g^3\right ) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{c+d x} \, dx}{507 d^3}-\frac{\left ((b c-a d)^3 g^3\right ) \int \frac{A+B \log \left (\frac{e (a+b x)}{c+d x}\right )}{(c+d x)^2} \, dx}{1521 d^3}\\ &=-\frac{A b^2 (2 b c-3 a d) g^3 x}{1521 d^3}+\frac{b^3 g^3 x^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{3042 d^2}+\frac{(b c-a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^4 (c+d x)}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{507 d^4}-\frac{\left (b^3 B g^3\right ) \int \frac{(b c-a d) x^2}{(a+b x) (c+d x)} \, dx}{3042 d^2}-\frac{\left (b^2 B (2 b c-3 a d) g^3\right ) \int \log \left (\frac{e (a+b x)}{c+d x}\right ) \, dx}{1521 d^3}-\frac{\left (b B (b c-a d)^2 g^3\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{e (a+b x)} \, dx}{507 d^4}-\frac{\left (B (b c-a d)^3 g^3\right ) \int \frac{b c-a d}{(a+b x) (c+d x)^2} \, dx}{1521 d^4}\\ &=-\frac{A b^2 (2 b c-3 a d) g^3 x}{1521 d^3}-\frac{b B (2 b c-3 a d) g^3 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1521 d^3}+\frac{b^3 g^3 x^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{3042 d^2}+\frac{(b c-a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^4 (c+d x)}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{507 d^4}-\frac{\left (b^3 B (b c-a d) g^3\right ) \int \frac{x^2}{(a+b x) (c+d x)} \, dx}{3042 d^2}+\frac{\left (b B (2 b c-3 a d) (b c-a d) g^3\right ) \int \frac{1}{c+d x} \, dx}{1521 d^3}-\frac{\left (B (b c-a d)^4 g^3\right ) \int \frac{1}{(a+b x) (c+d x)^2} \, dx}{1521 d^4}-\frac{\left (b B (b c-a d)^2 g^3\right ) \int \frac{(c+d x) \left (-\frac{d e (a+b x)}{(c+d x)^2}+\frac{b e}{c+d x}\right ) \log (c+d x)}{a+b x} \, dx}{507 d^4 e}\\ &=-\frac{A b^2 (2 b c-3 a d) g^3 x}{1521 d^3}-\frac{b B (2 b c-3 a d) g^3 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1521 d^3}+\frac{b^3 g^3 x^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{3042 d^2}+\frac{(b c-a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^4 (c+d x)}+\frac{b B (2 b c-3 a d) (b c-a d) g^3 \log (c+d x)}{1521 d^4}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{507 d^4}-\frac{\left (b^3 B (b c-a d) g^3\right ) \int \left (\frac{1}{b d}+\frac{a^2}{b (b c-a d) (a+b x)}+\frac{c^2}{d (-b c+a d) (c+d x)}\right ) \, dx}{3042 d^2}-\frac{\left (B (b c-a d)^4 g^3\right ) \int \left (\frac{b^2}{(b c-a d)^2 (a+b x)}-\frac{d}{(b c-a d) (c+d x)^2}-\frac{b d}{(b c-a d)^2 (c+d x)}\right ) \, dx}{1521 d^4}-\frac{\left (b B (b c-a d)^2 g^3\right ) \int \left (\frac{b e \log (c+d x)}{a+b x}-\frac{d e \log (c+d x)}{c+d x}\right ) \, dx}{507 d^4 e}\\ &=-\frac{A b^2 (2 b c-3 a d) g^3 x}{1521 d^3}-\frac{b^2 B (b c-a d) g^3 x}{3042 d^3}-\frac{B (b c-a d)^3 g^3}{1521 d^4 (c+d x)}-\frac{a^2 b B g^3 \log (a+b x)}{3042 d^2}-\frac{b B (b c-a d)^2 g^3 \log (a+b x)}{1521 d^4}-\frac{b B (2 b c-3 a d) g^3 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1521 d^3}+\frac{b^3 g^3 x^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{3042 d^2}+\frac{(b c-a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^4 (c+d x)}+\frac{b^3 B c^2 g^3 \log (c+d x)}{3042 d^4}+\frac{b B (2 b c-3 a d) (b c-a d) g^3 \log (c+d x)}{1521 d^4}+\frac{b B (b c-a d)^2 g^3 \log (c+d x)}{1521 d^4}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{507 d^4}-\frac{\left (b^2 B (b c-a d)^2 g^3\right ) \int \frac{\log (c+d x)}{a+b x} \, dx}{507 d^4}+\frac{\left (b B (b c-a d)^2 g^3\right ) \int \frac{\log (c+d x)}{c+d x} \, dx}{507 d^3}\\ &=-\frac{A b^2 (2 b c-3 a d) g^3 x}{1521 d^3}-\frac{b^2 B (b c-a d) g^3 x}{3042 d^3}-\frac{B (b c-a d)^3 g^3}{1521 d^4 (c+d x)}-\frac{a^2 b B g^3 \log (a+b x)}{3042 d^2}-\frac{b B (b c-a d)^2 g^3 \log (a+b x)}{1521 d^4}-\frac{b B (2 b c-3 a d) g^3 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1521 d^3}+\frac{b^3 g^3 x^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{3042 d^2}+\frac{(b c-a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^4 (c+d x)}+\frac{b^3 B c^2 g^3 \log (c+d x)}{3042 d^4}+\frac{b B (2 b c-3 a d) (b c-a d) g^3 \log (c+d x)}{1521 d^4}+\frac{b B (b c-a d)^2 g^3 \log (c+d x)}{1521 d^4}-\frac{b B (b c-a d)^2 g^3 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{507 d^4}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{507 d^4}+\frac{\left (b B (b c-a d)^2 g^3\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{x} \, dx,x,c+d x\right )}{507 d^4}+\frac{\left (b B (b c-a d)^2 g^3\right ) \int \frac{\log \left (\frac{d (a+b x)}{-b c+a d}\right )}{c+d x} \, dx}{507 d^3}\\ &=-\frac{A b^2 (2 b c-3 a d) g^3 x}{1521 d^3}-\frac{b^2 B (b c-a d) g^3 x}{3042 d^3}-\frac{B (b c-a d)^3 g^3}{1521 d^4 (c+d x)}-\frac{a^2 b B g^3 \log (a+b x)}{3042 d^2}-\frac{b B (b c-a d)^2 g^3 \log (a+b x)}{1521 d^4}-\frac{b B (2 b c-3 a d) g^3 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1521 d^3}+\frac{b^3 g^3 x^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{3042 d^2}+\frac{(b c-a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^4 (c+d x)}+\frac{b^3 B c^2 g^3 \log (c+d x)}{3042 d^4}+\frac{b B (2 b c-3 a d) (b c-a d) g^3 \log (c+d x)}{1521 d^4}+\frac{b B (b c-a d)^2 g^3 \log (c+d x)}{1521 d^4}-\frac{b B (b c-a d)^2 g^3 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{507 d^4}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{507 d^4}+\frac{b B (b c-a d)^2 g^3 \log ^2(c+d x)}{1014 d^4}+\frac{\left (b B (b c-a d)^2 g^3\right ) \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{b x}{-b c+a d}\right )}{x} \, dx,x,c+d x\right )}{507 d^4}\\ &=-\frac{A b^2 (2 b c-3 a d) g^3 x}{1521 d^3}-\frac{b^2 B (b c-a d) g^3 x}{3042 d^3}-\frac{B (b c-a d)^3 g^3}{1521 d^4 (c+d x)}-\frac{a^2 b B g^3 \log (a+b x)}{3042 d^2}-\frac{b B (b c-a d)^2 g^3 \log (a+b x)}{1521 d^4}-\frac{b B (2 b c-3 a d) g^3 (a+b x) \log \left (\frac{e (a+b x)}{c+d x}\right )}{1521 d^3}+\frac{b^3 g^3 x^2 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{3042 d^2}+\frac{(b c-a d)^3 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right )}{1521 d^4 (c+d x)}+\frac{b^3 B c^2 g^3 \log (c+d x)}{3042 d^4}+\frac{b B (2 b c-3 a d) (b c-a d) g^3 \log (c+d x)}{1521 d^4}+\frac{b B (b c-a d)^2 g^3 \log (c+d x)}{1521 d^4}-\frac{b B (b c-a d)^2 g^3 \log \left (-\frac{d (a+b x)}{b c-a d}\right ) \log (c+d x)}{507 d^4}+\frac{b (b c-a d)^2 g^3 \left (A+B \log \left (\frac{e (a+b x)}{c+d x}\right )\right ) \log (c+d x)}{507 d^4}+\frac{b B (b c-a d)^2 g^3 \log ^2(c+d x)}{1014 d^4}-\frac{b B (b c-a d)^2 g^3 \text{Li}_2\left (\frac{b (c+d x)}{b c-a d}\right )}{507 d^4}\\ \end{align*}

Mathematica [A]  time = 0.42726, size = 359, normalized size = 1.05 \[ \frac{g^3 \left (-3 b B (b c-a d)^2 \left (2 \text{PolyLog}\left (2,\frac{b (c+d x)}{b c-a d}\right )+\log (c+d x) \left (2 \log \left (\frac{d (a+b x)}{a d-b c}\right )-\log (c+d x)\right )\right )+b B \left (b \left (d x (a d-b c)+b c^2 \log (c+d x)\right )-a^2 d^2 \log (a+b x)\right )+b^3 d^2 x^2 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )-2 A b^2 d x (2 b c-3 a d)+6 b (b c-a d)^2 \log (c+d x) \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )+\frac{2 (b c-a d)^3 \left (B \log \left (\frac{e (a+b x)}{c+d x}\right )+A\right )}{c+d x}-2 b B d (a+b x) (2 b c-3 a d) \log \left (\frac{e (a+b x)}{c+d x}\right )+2 b B (2 b c-3 a d) (b c-a d) \log (c+d x)-2 B (b c-a d)^2 \left (\frac{b c-a d}{c+d x}+b \log (a+b x)-b \log (c+d x)\right )\right )}{2 d^4 i^2} \]

Antiderivative was successfully verified.

[In]

Integrate[((a*g + b*g*x)^3*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(c*i + d*i*x)^2,x]

[Out]

(g^3*(-2*A*b^2*d*(2*b*c - 3*a*d)*x - 2*b*B*d*(2*b*c - 3*a*d)*(a + b*x)*Log[(e*(a + b*x))/(c + d*x)] + b^3*d^2*
x^2*(A + B*Log[(e*(a + b*x))/(c + d*x)]) + (2*(b*c - a*d)^3*(A + B*Log[(e*(a + b*x))/(c + d*x)]))/(c + d*x) +
2*b*B*(2*b*c - 3*a*d)*(b*c - a*d)*Log[c + d*x] + 6*b*(b*c - a*d)^2*(A + B*Log[(e*(a + b*x))/(c + d*x)])*Log[c
+ d*x] - 2*B*(b*c - a*d)^2*((b*c - a*d)/(c + d*x) + b*Log[a + b*x] - b*Log[c + d*x]) + b*B*(-(a^2*d^2*Log[a +
b*x]) + b*(d*(-(b*c) + a*d)*x + b*c^2*Log[c + d*x])) - 3*b*B*(b*c - a*d)^2*((2*Log[(d*(a + b*x))/(-(b*c) + a*d
)] - Log[c + d*x])*Log[c + d*x] + 2*PolyLog[2, (b*(c + d*x))/(b*c - a*d)])))/(2*d^4*i^2)

________________________________________________________________________________________

Maple [B]  time = 0.174, size = 2973, normalized size = 8.7 \begin{align*} \text{output too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*g*x+a*g)^3*(A+B*ln(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x)

[Out]

-1/d*A*g^3/i^2*a^3/(d*x+c)+1/d*B*g^3/i^2*a^3/(d*x+c)-1/d^2*A*g^3/i^2*a^2*b+1/d^4*B*g^3/i^2*b^3*c^2+2*e^2/d^3*B
*g^3/i^2*b^4*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*a/(d*x+c)^2*c^3-3*e^2/d^2*B*g^3/i
^2*b^3*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*a^2/(d*x+c)^2*c^2-9*e/d^2*B*g^3/i^2*b^2
*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*c/(d*x+c)*a^2+9*e/d^3*B*g^3/i^2*b^3*ln(b*e/d+(a
*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*c^2/(d*x+c)*a+2*e^2/d*B*g^3/i^2*b^2*ln(b*e/d+(a*d-b*c)*e/d/
(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*a^3/(d*x+c)^2*c-3*e/d^4*B*g^3/i^2*b^4*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))
/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*c^3/(d*x+c)+3*e/d*B*g^3/i^2*b*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/
(d*x+c)*b*c)*a^3/(d*x+c)-1/2*e^2/d^4*B*g^3/i^2*b^5*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*
c)^2*c^4/(d*x+c)^2-6*e/d^3*B*g^3/i^2*b^3*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*c*a-e^2
/d^3*B*g^3/i^2*b^4*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*c*a-3/d^2*B*g^3/i^2*b*dilog
(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*a^2+1/d^4*A*g^3/i^2*b^3*c^3/(d*x+c)-1/d^4*B*g^3/i^2*b^3*c^3/(d*x+
c)-3/d^4*B*g^3/i^2*b^3*dilog(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*c^2-5/2/d^2*B*g^3/i^2*b*ln(d*(b*e/d+(
a*d-b*c)*e/d/(d*x+c))-b*e)*a^2-5/2/d^4*B*g^3/i^2*b^3*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)*c^2-3/d^2*A*g^3/i
^2*b*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)*a^2-1/d^4*B*g^3/i^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*b^3*c^2-1/d^2
*B*g^3/i^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*a^2*b-1/d*B*g^3/i^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*a^3/(d*x+c)-3/d
^4*A*g^3/i^2*b^3*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)*c^2-1/d^4*A*g^3/i^2*b^3*c^2-3/d^2*B*g^3/i^2*a^2/(d*x+
c)*b*c+3/d^3*B*g^3/i^2*b^2*c^2/(d*x+c)*a+1/d^4*B*g^3/i^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*b^3*c^3/(d*x+c)-3/d^2
*B*g^3/i^2*b*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*ln(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*a^2+2/d^3*A*g^3/i^
2*a*b^2*c-2/d^3*B*g^3/i^2*b^2*c*a+3*e/d^4*A*g^3/i^2*b^4/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*c^2+1/2*e/d^2*B*g^3/i^2*
b^2/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*a^2+1/2*e/d^4*B*g^3/i^2*b^4/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*c^2+6/d^3*B*g^3/i^
2*b^2*dilog(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*a*c-3/d^3*A*g^3/i^2*a/(d*x+c)*b^2*c^2+5/d^3*B*g^3/i^2*
b^2*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)*a*c+1/2*e^2/d^2*A*g^3/i^2*b^3/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*a^2+
1/2*e^2/d^4*A*g^3/i^2*b^5/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*c^2+3*e/d^2*A*g^3/i^2*b^2/(d*e/(d*x+c)*a-e/(d*x+c)*b
*c)*a^2-3/d^4*B*g^3/i^2*b^3*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*ln(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*c^2
+2/d^3*B*g^3/i^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*b^2*c*a+6/d^3*A*g^3/i^2*b^2*ln(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c)
)-b*e)*c*a+3/d^2*A*g^3/i^2*a^2/(d*x+c)*b*c+1/d^2*B*g^3/i^2*b*a^2-6*e/d^3*A*g^3/i^2*b^3/(d*e/(d*x+c)*a-e/(d*x+c
)*b*c)*a*c-e/d^3*B*g^3/i^2*b^3/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*a*c-e^2/d^3*A*g^3/i^2*b^4/(d*e/(d*x+c)*a-e/(d*x+c
)*b*c)^2*a*c-1/2*e^2*B*g^3/i^2*b*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*a^4/(d*x+c)^2
+6/d^3*B*g^3/i^2*b^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*ln(-(d*(b*e/d+(a*d-b*c)*e/d/(d*x+c))-b*e)/b/e)*a*c-3/d^3*
B*g^3/i^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*b^2*c^2/(d*x+c)*a+3/d^2*B*g^3/i^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))*b*
c/(d*x+c)*a^2+3*e/d^4*B*g^3/i^2*b^4*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*c^2+3*e/d^2*
B*g^3/i^2*b^2*ln(b*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)*a^2+1/2*e^2/d^4*B*g^3/i^2*b^5*ln(b
*e/d+(a*d-b*c)*e/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*c^2+1/2*e^2/d^2*B*g^3/i^2*b^3*ln(b*e/d+(a*d-b*c)*e
/d/(d*x+c))/(d*e/(d*x+c)*a-e/(d*x+c)*b*c)^2*a^2

________________________________________________________________________________________

Maxima [B]  time = 1.5938, size = 1810, normalized size = 5.31 \begin{align*} \text{result too large to display} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^3*(A+B*log(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x, algorithm="maxima")

[Out]

1/2*(2*c^3/(d^5*i^2*x + c*d^4*i^2) + 6*c^2*log(d*x + c)/(d^4*i^2) + (d*x^2 - 4*c*x)/(d^3*i^2))*A*b^3*g^3 - 3*A
*a*b^2*(c^2/(d^4*i^2*x + c*d^3*i^2) - x/(d^2*i^2) + 2*c*log(d*x + c)/(d^3*i^2))*g^3 + 3*A*a^2*b*g^3*(c/(d^3*i^
2*x + c*d^2*i^2) + log(d*x + c)/(d^2*i^2)) - B*a^3*g^3*(log(b*e*x/(d*x + c) + a*e/(d*x + c))/(d^2*i^2*x + c*d*
i^2) - 1/(d^2*i^2*x + c*d*i^2) - b*log(b*x + a)/((b*c*d - a*d^2)*i^2) + b*log(d*x + c)/((b*c*d - a*d^2)*i^2))
- A*a^3*g^3/(d^2*i^2*x + c*d*i^2) - 1/2*(6*a^3*b*d^3*g^3*log(e) - (6*g^3*log(e) + 7*g^3)*b^4*c^3 + (18*g^3*log
(e) + 17*g^3)*a*b^3*c^2*d - 6*(3*g^3*log(e) + 2*g^3)*a^2*b^2*c*d^2)*B*log(d*x + c)/(b*c*d^4*i^2 - a*d^5*i^2) +
1/2*((b^4*c*d^3*g^3*log(e) - a*b^3*d^4*g^3*log(e))*B*x^3 - ((3*g^3*log(e) + g^3)*b^4*c^2*d^2 - (9*g^3*log(e)
+ 2*g^3)*a*b^3*c*d^3 + (6*g^3*log(e) + g^3)*a^2*b^2*d^4)*B*x^2 - ((4*g^3*log(e) + g^3)*b^4*c^3*d - 2*(5*g^3*lo
g(e) + g^3)*a*b^3*c^2*d^2 + (6*g^3*log(e) + g^3)*a^2*b^2*c*d^3)*B*x - 3*((b^4*c^3*d*g^3 - 3*a*b^3*c^2*d^2*g^3
+ 3*a^2*b^2*c*d^3*g^3 - a^3*b*d^4*g^3)*B*x + (b^4*c^4*g^3 - 3*a*b^3*c^3*d*g^3 + 3*a^2*b^2*c^2*d^2*g^3 - a^3*b*
c*d^3*g^3)*B)*log(d*x + c)^2 + 2*((g^3*log(e) - g^3)*b^4*c^4 - 4*(g^3*log(e) - g^3)*a*b^3*c^3*d + 6*(g^3*log(e
) - g^3)*a^2*b^2*c^2*d^2 - 3*(g^3*log(e) - g^3)*a^3*b*c*d^3)*B + ((b^4*c*d^3*g^3 - a*b^3*d^4*g^3)*B*x^3 - 3*(b
^4*c^2*d^2*g^3 - 3*a*b^3*c*d^3*g^3 + 2*a^2*b^2*d^4*g^3)*B*x^2 - (6*b^4*c^3*d*g^3 - 12*a*b^3*c^2*d^2*g^3 + 3*a^
2*b^2*c*d^3*g^3 + 5*a^3*b*d^4*g^3)*B*x - (6*a*b^3*c^3*d*g^3 - 15*a^2*b^2*c^2*d^2*g^3 + 11*a^3*b*c*d^3*g^3)*B)*
log(b*x + a) - ((b^4*c*d^3*g^3 - a*b^3*d^4*g^3)*B*x^3 - 3*(b^4*c^2*d^2*g^3 - 3*a*b^3*c*d^3*g^3 + 2*a^2*b^2*d^4
*g^3)*B*x^2 - 2*(2*b^4*c^3*d*g^3 - 5*a*b^3*c^2*d^2*g^3 + 3*a^2*b^2*c*d^3*g^3)*B*x + 2*(b^4*c^4*g^3 - 4*a*b^3*c
^3*d*g^3 + 6*a^2*b^2*c^2*d^2*g^3 - 3*a^3*b*c*d^3*g^3)*B)*log(d*x + c))/(b*c^2*d^4*i^2 - a*c*d^5*i^2 + (b*c*d^5
*i^2 - a*d^6*i^2)*x) + 3*(b^3*c^2*g^3 - 2*a*b^2*c*d*g^3 + a^2*b*d^2*g^3)*(log(b*x + a)*log((b*d*x + a*d)/(b*c
- a*d) + 1) + dilog(-(b*d*x + a*d)/(b*c - a*d)))*B/(d^4*i^2)

________________________________________________________________________________________

Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{A b^{3} g^{3} x^{3} + 3 \, A a b^{2} g^{3} x^{2} + 3 \, A a^{2} b g^{3} x + A a^{3} g^{3} +{\left (B b^{3} g^{3} x^{3} + 3 \, B a b^{2} g^{3} x^{2} + 3 \, B a^{2} b g^{3} x + B a^{3} g^{3}\right )} \log \left (\frac{b e x + a e}{d x + c}\right )}{d^{2} i^{2} x^{2} + 2 \, c d i^{2} x + c^{2} i^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^3*(A+B*log(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x, algorithm="fricas")

[Out]

integral((A*b^3*g^3*x^3 + 3*A*a*b^2*g^3*x^2 + 3*A*a^2*b*g^3*x + A*a^3*g^3 + (B*b^3*g^3*x^3 + 3*B*a*b^2*g^3*x^2
+ 3*B*a^2*b*g^3*x + B*a^3*g^3)*log((b*e*x + a*e)/(d*x + c)))/(d^2*i^2*x^2 + 2*c*d*i^2*x + c^2*i^2), x)

________________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)**3*(A+B*ln(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)**2,x)

[Out]

Timed out

________________________________________________________________________________________

Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b g x + a g\right )}^{3}{\left (B \log \left (\frac{{\left (b x + a\right )} e}{d x + c}\right ) + A\right )}}{{\left (d i x + c i\right )}^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*g*x+a*g)^3*(A+B*log(e*(b*x+a)/(d*x+c)))/(d*i*x+c*i)^2,x, algorithm="giac")

[Out]

integrate((b*g*x + a*g)^3*(B*log((b*x + a)*e/(d*x + c)) + A)/(d*i*x + c*i)^2, x)